Write a LMC program that can convert an n-bit binary number into a decimal number. Display the natural number as output before halting the program. The first input determines the value for n. It is assumed this value will be equal to four, or greater. For example, if the first input is eight (8) then eight subsequent inputs are requested. If the subsequent inputs number were 1, 0, 0, 1, 0, 0, 0, 0 then the output would be 9.n input values are provided by the user, one for each bit: The first of these is the least-significant bit. The n’th input is the most-significant bit.

MY attempt:

   IN
   BRZ INVALID_N
   STO N
   LDA N
   SUB FOUR
   BRP VALID_N

INVALID_N:HLT
VALID_N:LDA ZERO
STO RESULT
LDA ONE
STO POWER
LOOP: BRZ OUTPUT
STO COUNT
IN
BRZ NEXT
LDA RESULT
ADD POWER
STO RESULT
NEXT: LDA POWER
ADD POWER
STO POWER
LDA COUNT
SUB ONE
BR LOOP
OUTPUT: LDA RESULT
OUT
BR LOOP
ZERO: HLT
ONE: DAT 1
POWER: DAT 32
COUNT: DAT 1
RESULT: DAT 21
N: DAT 0
FOUR: DAT 4

Even though my code converts n binary thats is greater and equal to the 4. it keeps showing “LMC out basket” every time i enter the n binary digits. And it keeps looping even after converting the n binary in decimal