How to get data member names with source_location::function_name

  Kiến thức lập trình

After reading this source (and also my answer) and this source, I got the impression that we can use std::source_location::function_name to extract names of data members.

Let’s say we are given some struct_t type with an instance of my_struct. Further, the following properties are valid for struct_t:

  1. The number of non-static data members is 3;
  2. The following line compiles successfully and has the expected
    behavior:auto& [a,b,c] = my_struct;;
  3. Any additional assumptions if this is really necessary

Q: How to use C++20 without other libs and std::source_location::function_name to extract all non-static data member names from struct_t? The correct answer should be easily generalized to an arbitrary number of fields and also be compatible with g++, clang, and MSVC.

Proof of concept, but it is not compatible with MSVC and it looks strange:

#include <iostream>
#include <type_traits>
#include <source_location>
#include <vector>
#include <string_view>
#include <array>    

struct struct_t {
    int field1;
    double field2;
    std::vector<int> field3;

template<void* p>
std::string_view get(){
      return std::source_location::current().function_name();

template<class T>
auto fields3(T&& st){
    static auto inst{std::forward<T>(st)};//bad. Needs a copy or move constructor 
    auto& [a,b,c]=inst;
    return std::array{get<(void*)&a>(), get<(void*)&b>(), get<(void*)&c>()};

int main()
    for (auto field:fields3(struct_t{})){
    //std::string_view get() [p = &inst.field1]
    //std::string_view get() [p = &inst.field2]
    //std::string_view get() [p = &inst.field3]
    return 0;