For a 16 bit word with 6 bits for an opcode
- How many different instructions could I fit into the instruction set?
- What is the largest number that I could use as data?
- Number of instructions: 26 = 64
- largest operand: 210 – 1 = 1023
My question is how did they calculated 210 from 16 bit word?
If a number takes up 16 bits, and you use 6 of them for something, that leaves 10 bits.