Why typescript doesn’t produce errors with generic parameter of argument in class?
I want to define class with generic parameter T and some methods operating with instances of the same class with the same parameter T.
But it doesn’t produce type errors as I expect.
Why does typescript doesn’t produce errors with generic parameter of argument in class?
I want to define class with generic parameter T and some methods operating with instances of the same class with the same parameter T.
But it doesn’t produce type errors as I expect.
Unable to share discriminated union type and generic types in Typescript?
I’m using typescript 5.4.5, and I have the following utility helpers:
Inferring different types based on null value in Typescript
I want to be able to infer different types based on whether the value of a parameter is null or not. Here is what I have:
TypeScript Table rows types build based on column definition
Im trying(and failing) to build table generator based on row and column arrays.
Extract a union of nested keys from an interface
I’m trying to get a union type made out of keys that are nested within the ‘indexes’ like in the code below.
How to specify specific key in Generic type?
type Wrapper<P extends string> = { [P]: string; }; type Wrapped = Wrapper<‘key’>; // valid const wrapped: Wrapped = { key: ‘string’ }; // invalid const wrapped: Wrapped = { k: ‘string’ }; Here we have wrapper with type param P that I want to use to specify a specific key. But it doesn’t looks […]
How to exclude the second value in a generic
I have a code:
Typescript complaining ‘T’ could be instantiated with a different subtype of constraint ‘MyType’
I’m trying to understand this error, but I can’t seem to make sense of it… I’m using some Typescript features that are fairly new to me (conditional types), so I could just be misunderstanding how they work.
Get generic type of a key in a class
In Konva we have a class like this: