Say I have the following type ..
Intuitively it seems there shouldn’t be any error..
I have type ILoadedValue<TValue>
, which should be used as a wrapper for types, which can be undefined
, but prevent usages when TValue
can not be undefined
(because in such cases it is more efficient to not wrap type, but to use undefined
to indicate that type is still being l..
My existing JavaScript code has “records” where the id is numeric and the other attributes are strings. I’m trying to define this..
i recently have learnt typescript, i encountered an error that i think i should write type narrower for it or something like..
‘Util’ implicitly has type ‘any’ because it does not have a type annotation and is referenced directly or indirectly in its own initializer.ts(7022) why does this error appear? why does my object have an “any” type? its an object. And for some reason whenever i remove the first property from it the error goes awayenter ..
I am seeing a weird behavior and would appreciate some help. Here is my ..
I have some objects which supply many operations, some of which are not valid depending on the runtime (yet constant) state of the object. I wish to use TypeScript to restrict the set of operations available on the object, so that the incompatible ones cannot be c..
I have to change a specific strings defined as 'GET' | 'POST' | 'PATCH' | 'DELETE'
to lowercase, without losing information about type. When I do just method.toLowerCase()
, it changes its type back to string
. I have to achieve something like 'get' | 'post' | 'patch' | 'delete'
. I was able to do this using Generics and Type assertion, like..