How do I evaluate this code un-deterministically?

As the title asks, why does Racket output a 1 for a logical and between 0 1? The interesting this here is that the same operation but flipped positions of 0 and 1 give the proper output of 0. I’m no Racket/Scheme expert, but shouldn’t a logical and of 0 1 return 0 or #f in Racket?

I’m developing a Scheme program where I aim to parse a custom language using the sllgen library, focusing on handling try-catch-finally blocks. However, I’m encountering an error related to list manipulation with the caddr function.

I have a struct