Lost on how to separate columns
I want to separate a column of my dataset into different columns. However, the problem is that the column of interest is dirty and does not split the I want. This is the column I have.
Lost on how to separate columns
I want to separate a column of my dataset into different columns. However, the problem is that the column of interest is dirty and does not split the I want. This is the column I have.
Issue with stringr::str_replace function when patterns are present as a column in dataframe
I have a requirement to replace the following values to corresponding vector elements in the data frame.
How to extract last digit using str_sub in R
I have a dataframe like this:
How to insert characters after a pattern using stringr?
I have a character vector
What is the correct syntax for specifying length for positive look behind?
I have a series of expressions that start with numbers of different length and I would like to extract the string after these numbers: e.g. c(“14ac”, “148me3”) I would like to get c(“ac”, “me3).
What is the most elegent way to insert characters (passed on as a vector) at a certain position in the string (passed on as vector) using stringr?
I need to insert the following characters: c(“me3”, “ac”) in positions c(1, 6) in the following string “KSTGGKAPR”. What is the most elegant way to do this? Can I avoid writing a loop?
Why does str_sub (from stringr) report an error when the string is passed to it explicitly, while it works if the string is passed as a variable?
On my computer:
how to replace all occurrences of a certain character, but not if the character is the first in string?
I have the following vector
How to perform replacements containing square brackets with string_replace()?
I have a vector with two elements: