Date functions: trying to get dates 6 months in advance with certain criteria
I need to track attendance and progress over 6 months, I have to schedule meetings monthly to check in with clients, I work part time Monday to Wednesday so the meetings have to be on these days. I am new to python and I am having trouble Writing a code in python which generates dates six months from a start date, but only returns dates Monday to Wednesday and excludes weekend. I also need to excluded holidays.
Any help is appreciated. Thanks in advance
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This question already has an answer here: Why does datetime.datetime.now() – datetime.datetime.now() equal to datetime.timedelta(-1, 86399, 999974)? (1 answer) Closed 1 hour ago. I’m working with python 3.12.4 and using the standard library datetime. I am expecting the difference between two datetime.now to be zero. Instead I get a number like 86399. import datetime print((datetime.datetime.now() […]
python `(datetime.datetime.now() – datetime.datetime.now()).seconds` does not return 0 seconds [duplicate]
This question already has an answer here: Why does datetime.datetime.now() – datetime.datetime.now() equal to datetime.timedelta(-1, 86399, 999974)? (1 answer) Closed 1 hour ago. I’m working with python 3.12.4 and using the standard library datetime. I am expecting the difference between two datetime.now to be zero. Instead I get a number like 86399. import datetime print((datetime.datetime.now() […]
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