This question already has answers here: Strange behavior of foreach when using reference: foreach ($a as &$v) { … } (3 answers) PHP Foreach Pass by Reference: Last Element Duplicating? (Bug?) [duplicate] (5 answers) Closed 1 hour ago. The following PHP code: $products = [ [‘id’ => 1], [‘id’ => 2], [‘id’ => 3] ]; […]

This question already has answers here: Strange behavior of foreach when using reference: foreach ($a as &$v) { … } (3 answers) PHP Foreach Pass by Reference: Last Element Duplicating? (Bug?) [duplicate] (5 answers) Closed 1 hour ago. The following PHP code: $products = [ [‘id’ => 1], [‘id’ => 2], [‘id’ => 3] ]; […]

This question already has answers here: Strange behavior of foreach when using reference: foreach ($a as &$v) { … } (3 answers) PHP Foreach Pass by Reference: Last Element Duplicating? (Bug?) [duplicate] (5 answers) Closed 1 hour ago. The following PHP code: $products = [ [‘id’ => 1], [‘id’ => 2], [‘id’ => 3] ]; […]

This question already has answers here: Strange behavior of foreach when using reference: foreach ($a as &$v) { … } (3 answers) PHP Foreach Pass by Reference: Last Element Duplicating? (Bug?) [duplicate] (5 answers) Closed 1 hour ago. The following PHP code: $products = [ [‘id’ => 1], [‘id’ => 2], [‘id’ => 3] ]; […]

<?php $array = [[‘Example’ => ‘Value’]]; function hello(&$array) { foreach ($array as &$member) { $member[‘Test’] = true; } } var_dump($array); Consider the above. Why is it that ‘Test’ => true is not added to the array member [‘Example’ => ‘Value’]? I’ve passed references down the line, so $member should be a name referring to the […]

I’m trying to pass an object to a function in PHP to split a long function. The first example is the working way with the long funcion: