C++ Primer 5th Ed – Stanley. Section 16.1.3 – one-to-one friendship. Question on template syntax
I’m studying C++ templating on the above section and i came across the below syntax.
In C++, how do I write templates that access a type’s member variable but skips if the member variable is not in the type
I have to set different member variables based on the types supplied to a template. But the problem is all of the members I’m trying to set are not in types that gets used by the template.
Is it possible to have arrays of mixed C++ templates with known identical SizeOf?
As an example, I have a slab of code something like this:
Metaprogramming: Typedef of std::function argument list
I’m building a plugin for an engine, and I’m aiming to do as much templating and metaprogramming as I can because I will be making a version of this plugin for a different engine, as well.
How to eliminate variable declaration with template specialization?
In C++20, I’ve got a templated struct definition as below.
How to pack const reference in template parameter to std::array?
In C++20 or later, how to pack the const references of constexpr objects in template parameter list to an array? Something like following code, noticing the ... is not in foo() but only in template <>.
C++ How to pack const reference in template parameter to std::array?
In C++20 or later, how to pack the const references of constexpr objects in template parameter list to an array? Something like following code, noticing the ... is not in foo() but only in template <>.
Getting argument type that depends on another argument
I have class “Vector” that has its size known at compile time. I have a following type: