Why are these constructs using pre and post-increment undefined behavior?
#include <stdio.h> int main(void) { int i = 0; i = i++ + ++i; printf(“%dn”, i); // 3 i = 1; i = (i++); printf(“%dn”, i); // 2 Should be 1, no ? volatile int u = 0; u = u++ + ++u; printf(“%dn”, u); // 1 u = 1; u = (u++); printf(“%dn”, u); […]
Why are these constructs using pre and post-increment undefined behavior?
#include <stdio.h> int main(void) { int i = 0; i = i++ + ++i; printf(“%dn”, i); // 3 i = 1; i = (i++); printf(“%dn”, i); // 2 Should be 1, no ? volatile int u = 0; u = u++ + ++u; printf(“%dn”, u); // 1 u = 1; u = (u++); printf(“%dn”, u); […]
Why are these constructs using pre and post-increment undefined behavior?
#include <stdio.h> int main(void) { int i = 0; i = i++ + ++i; printf(“%dn”, i); // 3 i = 1; i = (i++); printf(“%dn”, i); // 2 Should be 1, no ? volatile int u = 0; u = u++ + ++u; printf(“%dn”, u); // 1 u = 1; u = (u++); printf(“%dn”, u); […]
Why are these constructs using pre and post-increment undefined behavior?
#include <stdio.h> int main(void) { int i = 0; i = i++ + ++i; printf(“%dn”, i); // 3 i = 1; i = (i++); printf(“%dn”, i); // 2 Should be 1, no ? volatile int u = 0; u = u++ + ++u; printf(“%dn”, u); // 1 u = 1; u = (u++); printf(“%dn”, u); […]
Why are these constructs using pre and post-increment undefined behavior?
#include <stdio.h> int main(void) { int i = 0; i = i++ + ++i; printf(“%dn”, i); // 3 i = 1; i = (i++); printf(“%dn”, i); // 2 Should be 1, no ? volatile int u = 0; u = u++ + ++u; printf(“%dn”, u); // 1 u = 1; u = (u++); printf(“%dn”, u); […]
Why are these constructs using pre and post-increment undefined behavior?
#include <stdio.h> int main(void) { int i = 0; i = i++ + ++i; printf(“%dn”, i); // 3 i = 1; i = (i++); printf(“%dn”, i); // 2 Should be 1, no ? volatile int u = 0; u = u++ + ++u; printf(“%dn”, u); // 1 u = 1; u = (u++); printf(“%dn”, u); […]